The instantaneous displacement of a simple pendulum oscillator is given by `x= A cos (omegat+ pi / 4 )`Its speed will be maximum at time

The displacement of a simple harmonic oscillator is given by x = 4 cos (2pit+pi//4)m . Then velocity of the oscillator at t = 2 s is

The displacement of a particle is given by x = cos^(2) omegat. The motion is

The displacement equation of a simple harmonic oscillator is given by y=A sin omegat-Bcos omegat The amplitude of the oscillator will be

The displacement x of a particle in motion is given in terms of time by x(x-4) =1 -5 cos omegat

If a simple pendulum oscillates in water instead of air then the time period will -

The time period of a simple pendulum oscillating in a freely falling lift is

The instantaneous displacement x of a particle executing simple harmonic motion is given by x=a_1sinomegat+a_2cos(omegat+(pi)/(6)) . The amplitude A of oscillation is given by

The angular displacement of a simple pendulum is increased from 2^(@) to 4^(@) . Its frequency of oscillation