A ball is released from certain height. It loses 50% of its kinetic energy on striking the ground. It will attain a height again equal to

A ball is dropped from rest from a height of 0m. If it loses 20% of its kinetic energy on striing the ground, what is the height to which the ball bounces?

A ball at rest is dropped from a height of 12m . It loses 25% of its kinetic energy on striking the ground. Find the height to which it bounces.

A ball at rest is dropped from a height of 12m. It loses 25% of its kinetic energy in striking the ground , find the height to which it bounces. How do you account for the loss in kinetic energy ?

A ball at rest is dropped from a height of 12m. It loses 25% of its kinetic energy in striking the ground, find the height to which it bounces. How do you account for the loss in kinetic energy ?

A ball is dropped from rest at a height 12m.If is loses 25% of its kinetic engeryt of striking the ground,Calculate the height to which it bounces.

A ball at rest is dropped from a height of 12 m. It losses 25% of its kinetic energy on striking the ground and bounces back to a height 'h'. then value of 'h' is