The efficiency of a carnot cycle is `1/8` On decreasing the temperature of the sink by `65^(@)`C, the efficiency increases to `1/3`. Calculate the temperature of source (in `C^(@)`

The efficiency of a carnot cycle is 1//6 . On decreasing the tempertaure of the sink by 65^(@)C , the efficiency increases to 1//3 .Calculate the tempretaure of source and sink .

The efficiency of a Carnot cycle is 1//6 . By lowering the temperature of sink by 65 K , it increases to 1//3 . The initial and final temperature of the sink are

The efficiency of a Carnot cycle is 1//6 . If on reducing the temperature of the sink by 65^@C , the efficiency becomes 1//3 , find the source and sink temperatures between which the cycle is working.

The efficiency of a carnot engine is (1)/(6) . If the temperature of the sink is reduced by 62 K, the efficiency becomes (1)/(3) . The temperature of the source and the sink in the first case are respectively.

The temperature of sink of Carnot engine is 27^(@)C . Efficiency of engine is 25% . Then temeperature of source is

A reversible engine has an efficiency of 1/4 If the temperature of the sink is reduced by 58^(@) C, its efficiency becomes double. Calculate the temperature of the sink :

The efficiency of a Carnot engine operating between temperatures of 100^(@)C and -23^(@)C will be