A particle moves `21m` along the vector `6hat(i)+2hat(j)+3hat(k)` , then `14 m` along the vector `3hat(i)-2hat(j)+6hat(k)`. Its total displacement (in meters) is

Projection of the vector 2hat(i) + 3hat(j) + 2hat(k) on the vector hat(i) - 2hat(j) + 3hat(k) is :

Find the value of m so that the vector 3hat(i)-2hat(j)+hat(k) may be perpendicular to the vector 2hat(i)+6hat(j)+mhat(k) .

A particle moves from position 3hat(i)+2hat(j)-6hat(k) to 14hat(i)+13hat(j)+9hat(k) due to a uniform force of 4hat(i)+hat(j)+3hat(k)N . If the displacement is in meters, then find the work done by the force.

The component of vector A= 2hat(i)+3hat(j) along the vector hat(i)+hat(j) is

Find the angle between the vectors : vec(a)=2hat(i)-hat(j)+2hat(k) " and " vec(b)=6hat(i)+2hat(j)+3hat(k) .

A particle is moving with speed 6m/s along the direction of 2hat(i)+2hat(j)-hat(k) find the velocity vector of a particle ?

Find th esine of angles between vectors vec(a)= 2hat(i) - 6hat(j) - 3hat(k), and vec(b) = 4hat(i) + 3hat(j)- hat(k) ?

Find the dot product of two vectors vec(A)=3hat(i)+2hat(j)-4hat(k) and vec(B)=2hat(i)-3hat(j)-6hat(k) .

The sine of the angle between vectors vec(a)=2hat(i)-6hat(j)-3hat(k) and vec(b)=4hat(i)+3hat(j)-hat(k)

Given two vectors vec(A) = -hat(i) + 2hat(j) - 3hat(k) and vec(B) = 4hat(i) - 2hat(j) + 6hat(k) . The angle made by (A+B) with x-axis is :