For the reaction `2H_(2) + 2NO rarr N_(2) + 2H_(2)O`, the following mechanism has been suggested :
`2NO ? N_(2)O_(2)` equilibrium constant `K_(1)` (fast)
`N_(2)O_(2) +H_(2) overset(k_(2)) rarr N_(2)O +H_(2)O` (slow)
`N_(2) O +H_(2) overset(k_(3)) rarr N_(2)+H_(2)O` (fast)
Establish the rate law for given reaction.

For a reaction, 2NO + 2H_(2) to N_(2) + 2H_(2) O , the possible mechanism is NO hArr N_(2)O_(2) N_(2)O_(2) + H_(2) overset("Slow")(to) N_(2)O + H_(2) O N_(2) O + H_(2) O overset("fast")(to) N_(2) + H_(2) O What is the rate law and order of the reaction?

The reaction 2H_(2)O_(2) rarr 2H_(2)O+O_(2) is r=k[H_(2)O_(2)]

The possible mechanism for the reaction 2NO + 2H_(2) to N_(2) + 2H_(2)O is i) 2NO ltimplies N_(2)O_(2) ii) N_(2)O_(2) + H_(2) overset("slow")to N_(2)O+H_(2)O iii) N_(2)O + H_(2) overset("fast")to N_(2) + H_(2)O a) What is rate law for the reaction? b) What is the order of the reaction?

The mechanism of the reaction 2NO + O_(2) rarr 2NO_(2) is NO + NO underset(k_(-1))overset(k_(1))hArr N_(2)O_(2) ("fast") N_(2)O_(2) + O_(2) overset(k_(2))rarr 2NO_(2) (slow) The rate constant of the reaction is

In the reaction x Mg + yHNO_3 rarr Mg (NO_(3))_(2) + N_2O+ H_2 O .

For the reaction mechanism of the reaction {:(2NO(g),+,2H_(2)(g)),(to N_(2)(g),+,2H_(2)O(g)):} {:("Step I",2NO,overset(k_(1))hArr,N_(2)O_(2),,,K_(eq)"(fast)"),("Step II",N_(2)O_(2)+H_(2),overset(k_(2))rarr,N_(2)O+H_(2)O,,"(slow)"),("Step III",N_(2)O+H_(2),overset(k_(3))rarrr,N_(2)+H_(2)O,,"(fast)"):} Expression of rate of reaction is (Take K_(eq) xx k_(2) = k')

The reaction, 2NO+2H_(2)rarr N_(2)+2H_(2)O has been assigned to follow the following mechanism I. NO+NO hArr N_(2)O_(2)" " (fast) II. N_(2)O_(2)+H_(2) rarr N_(2)O+H_(2)O " " (slow) III. N_(2)O +H_(2) rarr N_(2)+H_(2)O " " (fast) The rate constant of step II is 1.2 xx 10^(-4) "mole"^(-1)L"min"^(-1) while equilibrium constant of step I is 1.4 xx 10^(-2) . What is the rate of reaction when concentration of NO and H_(2) each is 0.5 mole L^(-1) ?