If the tangent and the normal to a rectangular hyperbola `xy = c^(2) `, at a point , cuts off intercepts `a_(1)" and " a_(2)` on the x- axis and `b_(1) b_(2)` on the y- axis, then `a_(1)a_(2) + b_(1) b_(2)` is equal to

If the tangent and normal to the rectangular hyperbola xy=16 at point (8,2) cut off intercepts a_(1),a_(2) on the x axis and b_(1)b_(2) on the y axis then a_(1)a_(2)+b_(1)b_(2)+7//2 equals

If the tangent and normal to the hyperbola x^(2) - y^(2) = 4 at a point cut off intercepts a_(1) and a^(2) respectively on the x-axis, and b_(1) and b_(2) respectively on the y-axis, then the value of a_(1)a_(2) + b_(1)b_(2) is

If the tangent and normal to a rectangular hyperbola cut off intercepts a_(1) and a_(2) on one axis and b_(1) and b_(2) on the other, then

If the intercepts made by tangent,normal to a rectangular x^(2)-y^(2)=a^(2) with x -axis are a_(1),a_(2) and with y-axis are b_(1),b_(2) then a_(1),a_(2)+b_(1)b_(2)=

If x != y and the sequences x, a_(1),a_(2),y and x,b_(1),b_(2) , y each are in A.P., then (a_(2)-a_(1))/(b_(2)-b_(1)) is

If the points (a_(1),b_(1))m(a_(2),b_(2))" and " (a_(1)-a_(2),b_(2)-b_(2)) are collinear, then prove that a_(1)/a_(2)=b_(1)/b_(2)

If the equation of the locus of a point equidistant from the points (a_(1),b_(1)) and (a_(2),b_(2)) is (a_(1)-a_(2))x+(b_(1)-b_(2))y+c=0 then the value of c is

If the equation of the locus of a point equidistant from the points (a_(1),b_(1)) and (a_(2),b_(2)) is (a_(1)-a_(2))x+(b_(1)-b_(2))y+c=0 then the value of c'is: