A particle of mass 5 m at rest suddenly breaks on its own into three fragments . Two fragments of mass m of each move along mutully perpendicular direction with speed v each . The energy released suring the process is

A particle of mass 4 m which is at rest explodes into three fragments. Two of the fragments each of mass m are found to move with a speed v each in mutually perpendicular directions. The total energy released in the process of explosion is ............

A body kept at rest explodes in four identical fragments and it is found that three of them move along mutually perpendicular directions with same kinetic energy K . Total energy released in the explosion is

A body of mass 4m at rest explodes into three pieces. Two of the pieces each of mass m move with a speed v each in mutually perpendicular directions. The total kinetic energy released is

A shell of mass m is at rest initially. It explodes into three fragments having masses in the ratio 2:2: 1. The fragments having equal masses fly off along mutually perpendicular directions with speed v. What will be the speed of the third (lighter) fragment ?

A particle of mass 4 m which is at rest explodes into masses m, m & 2m . Two of the fragments of masses m and 2m are found to move with equal speeds v each in opposite directions. The total mechanical energy released in the process of explosion is :-

A body of mass 1 kg at rest explodes into three fragments of masses in the ratio 1 : 1 : 3 . The two pieces of equal mass fly in mutually perpendicular directions with a speed of 30 m//s each . What is the velocity of the heavier fragment ?

A body of mass 5 kg explodes at rest into three fragments with masses in the ratio 1 : 1 : 3. The fragments with equal masses fly in mutually perpendicular directions with speeds of 21 m/s. The velocity of the heaviest fragment will be -

A body of mass 5 kg explodes at rest into three fragments with masses in the ratio 1 : 1 : 3. The fragments with equal masses fly in mutually perpendicular directions with speeds of 21 m/s . The velocity of the heaviest fragment will be

There is an object of mass 5m kept at rest in space. Suddenly it explodes in three parts of masses m , 2m and 2m . Two parts of equal masses are found to move with equal speeds v along perpendicular directions . If energy released in explosion is nmv^(2) , then find value of n .