Ultrafilteration And G.F.R

If f : R -> R and g : R -> R defined f(x)=|x| and g(x)=[x-3] for x in R [.] denotes the greatest integer function then {g(f(x)):(-8)/(5)ltxlt(8)/(5)} =

Let f : R to R be differentiable at c in R and f(c ) = 0 . If g(x) = |f(x) |, then at x = c, g is

If R is a set of real numbers and f : R to R is given by the relation f (x) = sin x, x in R and mapping g: R to R by the relation g(x)= x^2 , X in R , then prove that f o g ne g o f.

f:R rarr R,g:R rarr R are defined as f(x)=|x|,g(x)=[x]AA x in R[*] is denotes greatest integer function then {x in R:g[f(x)]<=f[g(x)]}=

If f:R rarr R are defined by f(x)=x-[x] and g(x)=[x] for x in R, where [x] is the greatest integer not ex-ceeding x, then for everyx in R,f(g(x))=

Let f and g be differentiable function of R such that g(x)<=0,AA x in R and consider h(x)={f(x)f or |f(x)|<=g(x) and g(x)f or f(x)

If the functions f: R to R and g: R to R be defined by f (x) = 2x+1, g(x) = x^2 - 2. Find the formulae for g o f and f o g.

Let f : R to R : f (x) =10x +7. Find the function g : R to R : g o f = f o g =I_(g)