A freely falling body takes `t` second to travel `(1//x)^(th)` distance then time of descent is

A freely falling body takes T second to travel first (1/x)th distance.Then,time of descent is

" A freely falling body takes "' second to travel first "(1/x)^(th)" distance.Then,time of descent is "

A freely falling body takes 't' second to travel first 1/xth distance.Then,time of descent is

For a freely falling body

A freely falling body travels-- of total distance in 5th second

If a freely falling body travels in the last second, a distance equal to the distance travelled by it in the first three second, the time of the travel is

The KE of a freely falling body

Distance travelled by a freely falling body in the nth second is equal to 'n' sec find the value of n

The distances covered by a freely falling body in its first, second, third, ……, b^(th) seconds of its motion