The ends of the hypotenuse of a right angled triangle are `(0,5)` and `(5,0)` .The locus of the third vertex is

The ends of the hypotenuse of a right angled triangle are (6, 0) and (0, 6). Find the locus of the thrid vertex.

The ends of hypotenuse of a right angled triangle are (5,0),(-5,0) and the locus of third vertex is lx^(2)+my^(2)=25 then l+m=

The ends of hypotenuse of a right angled triangle are (5,0),(-5,0) then the locus of third vertex is

The ends of hypotenuse of a right angled triangle are (a,0),(-a,0) then the locus of third vertex is

The ends of hypotenuse of a right angled triangle are (a,0),(-a,0) then the locus of third vertex is a) x^(2)-y^(2)=a^(2) b) x^(2)+y^(2)=a^(2) c) x^(2)+y^(2)+a^(2)=0 d) x^(2)-y^(2)+a^(2)=0

If two vertices joining the hypotenuse of a right angled triangle are (0,0) and (3,4) ,then the length of the median through the vertex having right angle is-

The ends of the hypotenuse of a right angled triangle vertex of triangle.are (6,0) and (0,6), then find the locus of third vertex of triangle.

If (2,4),(4,2) are the extremities of the hypotenuse of a right angled isosceles triangle,then the third vertex is

If the equation of the hypotenuse of a right - angled isosceles triangle is 3x+4y=4 and its opposite vertex is (2, 2), then the equations of the perpendicular and the base are respectively