Let a function `f:(1, oo)rarr(0, oo)` be defined by `f(x)=|1-(1)/(x)|`. Then f is

f:(0,oo)rarr(0,oo) defined by f(x)=x^(2) is

f:(-oo,oo)rarr(-oo,oo) defined by f(x)=|x| is

Let a function f:(2,oo)rarr[0,oo)"defined as " f(x) = (|x-3|)/(|x-2|), then f is

A function f:(0,oo)rarr[0,oo] is given by f(x)=|1-(1)/(x)|, then f(x) is (A) Injective but not surjective (B) Injective and bijective (C) Injective only (D) Surjective only

f:(-oo,oo)rarr(0,1] defined by f(x)=(1)/(x^(2)+1) is

Consider the function f : R rarr(0,oo) defined by f(x)=2^(x)+2^(|x|) The number of solutions of f(x)=2x+3 is

The function f : [0,oo)to[0,oo) defined by f(x)=(2x)/(1+2x) is

If the function f:[1,oo)to[1,oo) is defined by f(x)=2^(x(x-1)) then f^(-1) is

f:(0,oo)rarr(0,oo) defined by f(x)={2^(x),x in(0,1)5^(x),x in[1,oo) is

If f:[1, oo) rarr [2, oo) is defined by f(x)=x+1/x , find f^(-1)(x)