If `P` is in equilibrium then `T_(1)/T_(2)` is

If 'O' is at equilibrium then the values of the tension T_(1) and T_(2) respectively.

If O is at equilibrium then the values of the tension T_(1) and T_(2) are, ( 20 N is acting vertically downwards at O ).

The block is in equilibrium (i) T_(1)=(mgcosbeta)/(sin(alpha+beta))" "(ii)T_(2)=(mgcosalpha)/(sin(alpha+beta)) (iii)T_(1)/T_(2)=(cosbeta)/(cosalpha)" "(iv)T_(1)/T_(2)=(cosalpha)/(cosbeta)

The system shown in figure is in equilibrium. Find the magnitude of tension in each string, T_(1), T_(2), T_(3) and T_(4) ( g = 10 m//s^(-2))

Variation of equilibrium constan K with temperature is given by van't Hoff equation InK=(Delta_(r)S^(@))/R-(Delta_(r)H^(@))/(RT) for this equation, (Delta_(r)H^(@)) can be evaluated if equilibrium constans K_(1) and K_(2) at two temperature T_(1) and T_(2) are known. log(K_(2)/K_(1))=(Delta_(r)H^(@))/(2.303R)[1/T_(1)-1/T_(2)] Select the correct statement :

Variation of equilibrium constan K with temperature is given by van't Hoff equation InK=(Delta_(r)S^(@))/R-(Delta_(r)H^(@))/(RT) for this equation, (Delta_(r)H^(@)) can be evaluated if equilibrium constans K_(1) and K_(2) at two temperature T_(1) and T_(2) are known. log(K_(2)/K_(1))=(Delta_(r)H^(@))/(2.303R)[1/T_(1)-1/T_(2)] For an isomerization X(g)hArrY(g) the temperature dependency of equilibrium cohnstant is given by : lnK=2-(1000)/T The value of Delta_(r)S^(@) at 300 K is :

To the circle x^(2)+y^(2)=4 two tangents are drawn from P(-4,0), which touch the circle at T_(1) ,and T_(2) and a rhombus PT_(1)P'T_(2) is completed.Circumcentre of the triangle PT_(1)T_(2) is at

If K_1 is the equilibrium constant at temperature T_1 and K_2 is the equilibrium constant at temperature T_2 and If T_2 gt T_1 and reaction is endothermic then