Acceleration of a particle at any time t is `veca=(2thatj+3t^(2)hatj)m//s^(2)`.If initially particle is at rest, find the velocity of the particle at time t=2s.

The acceleration of paticle varies with time as : a(t) = 3t^(2) +4 If the initial velocity of particle is 2 m//s , find the velocity of particle at t = 3sec .

The velocity of a particle is zero at time t = 2s, then

The acceleration of a particle moving along a straight line is (6t^(2)-3t)cm/s^(2), at time t seconds,If the velocity of the particle at time 2 seconds be 10cm/s ,find its veloctiy at time t seconds.

Velocity and acceleration of a particle at time t=0 are u=(2 hati+3 hatj) m//s and a=(4 hati+3 hatj) m//s^2 respectively. Find the velocity and displacement if particle at t=2s.

Acceleration of a particle in x-y plane varies with time as a=(2t hati+3t^2 hatj) m//s^2 At time t =0, velocity of particle is 2 m//s along positive x direction and particle starts from origin. Find velocity and coordinates of particle at t=1s.

Velocity of a particle in x-y plane at any time t is v=(2t hati+3t^2 hatj) m//s At t=0, particle starts from the co-ordinates (2m,4m). Find (a) acceleration of the particle at t=1s. (b) position vector and co-ordinates of the particle at t=2s.

The positione of a particle is expressed as vecr = ( 4t^(2) hati + 2thatj) m, where t is time in second. Find the velocity o the particle at t = 3 s

The acceleration a of a particle in m/s^2 is give by a=18t^2+36t+120 . If the particle starts from rest, then velocity at end of 1 s is

A particle is given an initial velocity of vecu=(3 hati+4 hatj) m//s . Acceleration of the particle is veca=(3t^(2) +2 thatj) m//s^(2) . Find the velocity of particle at t=2s.

Velocity of a particle at any time t is v=(2 hati+2t hatj) m//s. Find acceleration and displacement of particle at t=1s. Can we apply v=u+at or not?