A battery of emf `epsilon_0 = 5V` and internal resistance `5 Omega` is connected across a long uniform wire AB of length 1m and resistance per unit length `5 Omegam^(-1)`. Two cells of `epsilon_1 = 1 V and epsilon_2 = 2V` are connected as shown in the figure.

A battery of emf 2V and internal resistance 0.5(Omega) is connected across a resistance in 1 second?

A battery of emf epsilon_0=10V is connected across a 1m long uniform wire having resistance 10Omega//m. Two cells of emf epsilon_1=2V and epsilon_2=4V having internal resistance 1Omega and 5Omega respectively are connected as shown in the figure. If a galvanometer shows no deflection at the point P , find the distance of point P from the point a .

An accumulator of emf 2 V and negligible internal resistance is connected across a uniform wire of length 10 m and resistance 30 Omega The appropriate terminals of a cell of emf 1.5 V and internal resistance 1 Omega is connected to one end of the wire and the other terminal of the cell is connected through a sensitive galvanometer to a slider on the wire. What is the length of the wire that will be required to produce zero deflection of the galvanometer? How will the balancing length change? (a) When a coil of resistance 5Omega is placed in series with the accumulator. (b) The cell of 1.5 V is shunted with 5 Omega resistor?

A secondary cell of emf 2 V and finternal resistance 0.1 Omega is connected to the ends of a uniform wire of length 1 m and resistacne 12 Omega .A primary cell of emf 1.5 V in series with a galvancometer is connected to two points on the wire. If the galvanometer shows no deflection find the distance between the points.

A battery of emf E_0=12V is connected across a 4 m long uniform wire having resistance 4Omega//m . The cell of small emfs epsilon_1=2V and epsilon_2=4V having internal resistance 2Omega and 6Omega respectivley are connected as shown in the figure. If galvanometer shows no diflection at the point N the distance of points N from the point A is equal to

A battery of emf E_(0) = 12 V is connected across a 4 m long uniform wire having resistance (4 Omega)/(m) . The cells of small emfs epsilon_(1) = 2 V and epsilon_(2) - 4 V having internal resistance 2 Omega and 6 Omega respectively, are connected as shown in the figure. If galvanometer shows no deflection at the point N , the distance of point N from teh point A is equal to

A battery of emf epsilon and internal resistance r is connected across a load resistance R_L . The plot between output power and load resistance is shown in the figure The value of emf epsilon and internal resistance r respectively will be

A battery of emf (epsilon) and internal resistance r is connected across a load resistance R_L The plot between output power and load resistance is shown in the figure. value of emf (epsilon) and internal resistance respectively will be