The angle of inclination of an inclined plane is `60^(@)`. Coefficient of friction between `10kg` body on it and its surface is `0.2, g= 10ms^(-2)`. The acceleration of the body down the plane in `ms^(-2)` is .

The coefficient of friction between a body and the surface of an inclined plane at 45^(@) is 0.5. if g=9.8m//s^(2) , the acceleration of the body downwards I m//s^(2) is

The acceleration of a moving body down a rough inclined plane is

A block is lying on an inclined plane which makes 60^(@) with the horizontal. If coefficient of friction between block and plane is 0.25 and g=10m//s^2 , , then acceleration of the block when it moves along the plane will be

A 20kg box is gently placed on a rough inclined plane of inclination 30^(@) with horizontal. The coefficient of sliding friction between the box and the plane is 0.5.Find the acceleration of the box down the incline.

block of mass 10 kg is kept on a rough inclined plane of angle 30° and coefficient of friction between the surfaces is u = 0.2. The acceleration of the block when a force F = 10 N is applied upward along the plane as shown in figure is (Take g = 10 ms^(-2) and sqrt3 = 1.7)

A block of mass 0.5 kg has an initial velocity of 10ms^(-1) down an inclined plane of angle 30^@ , the coefficient of friction between the block and the inclined surface is 0.2. The velocity of the block after it travels a distance of 10 m is

When a body slides down an inclined plane with coefficient of friction as mu_(k) , then its acceleration is given by .

A body starts from rest on a long inclined plane of slope 45^(@) . The coefficient of friction between the body and the plane varies as mu = 0.3 x , where x is the distance travelled down the plane. The body will have maximum speed (for g = 10 m//s^(2) ) when x =