The e.m.f. of a cell is 2.0 volt and the internal resistance is 0.1ohm. It is connected with a resistance of 3.9ohm. Then potential difference across the cell is :–

The emf of a cell is 2 V. When the terminals of the cell is connected to a resistance 4Omega . The potential difference across the terminals, if internal resistance of cell is 1Omega is

The emf of a daniel cell is 1.08 V. When the terminals of the cells are connected to a ressitance of 3Omega , the potential difference across the terminals is found to be 0.6 V. Then the internal resistance of the cell is

The cell has an emf of 2 V and the internal resistance of this cell is 0.1 Omega , it is connected to resistance of 3.9 Omega , the voltage across the cell will be

The cell has an emf of 2 V and the internal resistance of this cell is 0.1 Omega , it is connected to resistance of 3.9 Omega , the voltage across the cell will be

A dry cell of emf 1.6V and internal resistance 0.10 ohm is connected to a resistor of resistance R ohm. If the current drawn from the cell is 2A.

A dry cell of emf 1.6V and internal resistance 0.10 ohm is connected to a resistor of resistance R ohm. If the current drawn from the cell is 2A.