A library has 6 copies of one book,4 copies of each of two books, 6 copies of each of three books and single copies of 8 books. The number of arrangements of all the books is

If you have 5 copies of one book,4 copies of each of two books,6 copies each of three books and single copy of 8 books you may arrange it in

A library has a copies of one book, b copies each of two books, c copies each of three books, a single copy of d books. The total number of ways in which these books can be arranged in a shelf is equal to a. ((a+2b+3c+d)!)/(a !(b !)^2(c !)^3) b. ((a+2b+3c+d)!)/(a !(2b !)^(c !)^3) c. ((a+b+3c+d)!)/((c !)^3) d. ((a+2b+3c+d)!)/(a !(2b !)^(c !)^)

A library has 5 copies of one book, 4 copies of each of 2 books, 6 copies of ech of 3 books nad single copies of 8 books. In how many ways cn all books be arranged so that copies of the same book are always together?

Nu-body has two copies of each

A library has n different books and has p copies of each of the book. The number of ways of selecting two or more books from the library is: