A particle is moving in a circle of radius `r` centred at `O` with constant speed `v`. What is the change in velocity in moving from `A "to" B (/_ AOB = 40^@)` ?

In Fig. a particle is moving in a circle of radius r centred at O with constant speed v. what is the change in velocity in moving from A to B ? Given /_AOB = 40^(@) .

A particle is moving in a circle of radius r having centre at O with a constant speed v . The magnitude of change in velocity in moving from A to B is

A particle is moving in a circle or radius r centred at O with constant speed v. The change in velocity in moving from P to Q (angle POQ=40^(@)) is :

A particle is moving in a circle of radius having centre at 0. with a constant speed V. The magnitude at change in velocity in moving from A to B is 60°

A particle is moving an a cirle of radius 'r' and centre O with constant speed . What is the change in velocity in moving from A to B ? (If any angle between two velocity vector is theta .)

A particle is moving in a circle of radius r with speed v as shown in the figure. The magnitude of change in velocity in moving from P to Q is

If the body is moving in a circle of radius r with a constant speed v , its angular velocity is

A particle is moving on a circular path with a constant speed 'v'. Its change of velocity as it moves from A to B is:

A particle is moving in a circle with a constant speed. Its moving is