The resistance of the bulb filament is `100Omega` at a temperature of `100^(@)C` . If its temperature co-efficient of resistance be 0.005 per `5 ""^(@)C`, its resistance will becomes `200 Omega` at a temperature

The resistance of a bulb filmanet is 100Omega at a temperature of 100^@C . If its temperature coefficient of resistance be 0.005 per ^@C , its resistance will become 200 Omega at a temperature of

The resistance of a metallic conductor is 50Omega at a temperature of 100^(@)C .If its temperature coefficient of resistance is 0.005^(@)C^(-1) ,then its resistance will become 125Omega at a temperature of

The resistance of a coi is 4.2Omega at 100^(@)C and the temperature coefficient of resistance of its material is (0.004)/(.^(@)C) . Its resistance at 0^(@)C is

If the resistance of a conductor is 5 Omega at 50^(@)C and 7Omega at 100^(@)C then the mean temperature coefficient of resistance of the material is

The resistance of a conductor at 15^(@)C is 16 Omega and at 100^(@)C is 20 Omega . What will be the temperature coefficient of resistance of the conductor ?

A wire has a resistance of 3.1 Omega at 30°C and a resistance 4.5 Omega at 100°C. The temperature coefficient of resistance of the wire

The resistance of a platinum resistance thermometer is 3.14 Omega at 40^(@)C and 3.76 Omega at 100^(@)C . Calculate the temperature coefficient of resistance of platinum. What will be its resistance when the thermometer is immersed in melting ice ?

A conducting wire has resistance 16 Omega at 15^0 C and 20 Omega at 100^0 C find temperature of coeffecient of resistance