`A=[[cos((2 pi)/(33)),sin((2 pi)/(33))],[-sin((2 pi)/(33)),cos((2 pi)/(33))]]`, then `A^(2017)=`

If A=[[cos(2 pi/33),sin(2 pi/33)],[-sin(2 pi/33),cos(2 pi/33)]] , then A^2007 is

cos((2pi)/3)-sin((2pi)/3)=?

The value of the determinant |sin theta,cos theta,sin2 thetasin(theta+(2 pi)/(3)),cos(theta+(2 pi)/(3)),sin(2 theta+(4 pi)/(3))sin(theta-(2 pi)/(3)),cos(theta-(2 pi)/(3)),sin(2 theta-(4 pi)/(3))

sin m((pi)/(2)+x)+cos n((pi)/(2)-x)

sin((13pi)/3)sin((8pi)/3)+cos((2pi)/3)sin((5pi)/6)=1/2

Delta ABC, (sin ((2 pi) / (3) -A) + sin ((2 pi) / (3) -B) + sin ((2 pi) / (3) -C)) / (cos ( (pi) / (3) - (A) / (2)) * cos ((pi) / (3) - (B) / (2)) * cos ((pi) / (3) - (C) / (2))))

|[1,(3 pi)/(10),(2 pi)/(10)],[0,cos(3 pi)/(10),sin(2 pi)/(10)],[0,sin(3 pi)/(10),cos(2 pi)/(10)]|

(sin((pi)/(10))+sin(13(pi)/(10)))(cos^(2)((pi)/(6))-cos^(2)((pi)/(10))) is equal to

(cos^(2)pi)/(8)+(sin^(2)(3 pi))/(8)+(sin^(2)(5 pi))/(8_(sin)^(2))(7 pi)/(8)=2