If `tan theta_(1).tantheta_(2)=k`, then: `(cos(theta_(1)-theta_(2))/(cos(theta_(1)+theta_(2)))=`

If tan theta_(1)tan theta_(2)=k, then (cos(theta_(1)-theta_(2)))/(cos(theta_(1)+theta_(2)))=(1+k)/(1-k) b.(1-k)/(1+k) c.(k+1)/(k-1) d.(k-1)/(k+1)

if tan theta_(1)=k cot theta_(2) then find (cos(theta_(1)-theta_(2)))/(cos(theta_(1)+theta_(2)))=

If cos theta_(1)=2cos theta_(2), then tan((theta_(1)-theta_(2))/(2))tan((theta_(1)+theta_(2))/(2)) is equal to (a) (1)/(3)(b)-(1)/(3)(c)1(d)-1

If cos(theta_(1))=2cos(theta_(2)) then tan((theta_(1)-theta_(2))/(2))tan((theta_(1)+theta_(2))/(2))=( i) (1)/(3)(ii)-(1)/(3)(iii)1(iv)-1

If (cos(theta_(1)-theta_(2)))/(cos(theta_(1)+theta_(2)))+(cos(theta_(3)+theta_(4)))/(cos(theta_(3)-theta_(4)))=0, then tantheta_(1)tan theta_(2)tan theta_(3)tan theta_(4)=

If sintheta_(1)+sintheta_(2)+sintheta_(3)=3, then cos theta_(1)+cos theta_(2)+cos theta_(3)=

f theta_(1),theta_(2),theta_(3),theta_(4),theta_(5)in(0,(pi)/(2)), satisfying tan theta_(1)tan theta_(2)tan theta_(3)tan theta_(4)tan theta_(5)=1 then maximum_(2 value of )theta_(3)tan theta_(4)cos theta_(5) is cos theta_(1)cos theta_(2)cos theta_(3)cos theta_(4)cos theta_(5) is

(cos(theta_(1)-theta_(2)))/(cos(theta_(1)+theta_(2)))+(cos(theta_(3)+theta_(4)))/(cos(theta_(3)-theta_(4)))=0then(tan theta_(1)*tan theta_(2))/(cot theta_(2)*cot theta_(4))

given that tan(theta_(1)+theta_(2))=(tan theta_(1)+tan theta_(2))/(1-tan theta_(1)*tan theta_(2)) find (theta_(1)+theta_(2)) when tan theta_(1)=(1)/(2),tan theta_(2)=(1)/(3)

If sin theta_(1)+sin theta_(2)+sin theta_(3)=3, then cos theta_(1)+cos theta_(2)+cos theta_(3) is equal to 3(b)2(c)1(d)0