If one end of a diameter of the circle `2x^(2)+2y^(2)-4x-8y+2=0` is `(3,2),` the other end is

If one end of a diameter of the circle 2x^(2)+2y^(2)-4x-8y+2=0 is (-1,2), then the other end of the diameter is

If one end of a diameter of the circle 3x^(2)+3y^(2)-9x+6y+5=0 is (1,2), then the other end is

If one end of the a diameter of the circle 2x^(2)+2y^(2)-4x-8y+2=0 is (3,2), then find the other end of the diameter.

If one end of a diameter of the circle x^(2)+y^(2)-4x-6y+11=0 is (3, 4), then find the coordinates of the other end of the diameter.

If one end of a diameter of the circle x^(2) + y^(2) -4x-6y +11=0 is (3, 4), then find the coordinates of the other end of the diameter.

If the coordinates of one end of a diameter of the circles x^(2)+y^(2)+4x-8y+5=0 is (2,1),, the coordinates of the other end is

One of the diameter of the circle x^(2)+y^(2)-2x+4y-4=0 , is

If one end of a diameter of the circle . x^(2) + y^(2) - 4x - 6y + 11 = 0 is (8,4), show that co -ordinates of the other end are (-4, 2) .