In `Delta ABC,a/cos A= b/cos B =c/cos c` ; If `b=2` 'then the area of the triangle is

In a triangle ABC, a cos A+b cos B+ c cos C=

In a triangle ABC,if (cos A)/(a)=(cos B)/(b)=(cos C)/(c) and the side a=2 then area of triangle is and the side a=2

In a triangle ABC, cos A+cos B+cos C=

If in a Delta ABC,(cos A)/(a)=(cos B)/(b)=(cos C)/(c), then find the measures of angles A,B,C.

In a triangle ABC ,cos A + cos B + cos C = 3/2 , then the triangle ,is

In a triangle ABC,cos A+cos B+cos C