Home
Class 12
MATHS
Equation of the plane containing the str...

Equation of the plane containing the straight line `(x)/(2)= (y)/(3)= (z)/(4)` and perpendicular to the plane containing the straight lines `(x)/(3)= (y)/(4)= (z)/(2) and (x)/(4) = (y)/(2) = (z)/(3)` is

A

`x - 2y + z = 0`

B

`5x + 2y - 4z = 0`

C

`x + 2y - 2z = 0`

D

`3x + 2y - 3z = 0`

Text Solution

Verified by Experts

The correct Answer is:
A

The vector perepndicular to the plane :
`|(veci,j,hatk),(3,4,2),(4,2,3)|=veci(8)-j-10hatk`
The vector perpendicular to the plane to be found out
`|(veci,j,hatk),(8, -1, -10),(2,3,4)|=veci+30-j(32+20)+hatk(24+2)=26hati-52hatk+26k or -j+hatk`
Therefore, the plane is `x(1)+y(-2)+z(1)=0`
`x-2y+z=0`
Promotional Banner

Topper's Solved these Questions

  • JEE MAIN REVISION TEST - 1 (2020)

    VMC MODULES ENGLISH|Exercise MATHEMATICS - SECTION 2|5 Videos
  • JEE MAIN REVISION TEST - 30 | JEE -2020

    VMC MODULES ENGLISH|Exercise MATHEMATICS|25 Videos
  • JEE MAIN REVISION TEST - 1 | JEE - 2020

    VMC MODULES ENGLISH|Exercise MATHEMATICS ( SECTION 2)|5 Videos

Similar Questions

Explore conceptually related problems

Equation of the plane containing the straight line x/2=y/3=z/4 and perpendicular to the plane containing the straight lines x/2=y/4=z/2 and x/4=y/2=z/3 is

Find the equation of the plane which contains the line (x-1)/(2)= (y+1)/(-1) = (z-3)/(4) and is perpendicular to the plane x+2y +z= 12 .

Find the equation of the plane passing through the straight line (x-1)/2=(y+2)/(-3)=z/5 and perpendicular to the plane x-y+z+2=0.

Find the equation of the plane passing through the straight line (x-1)/2=(y+2)/(-3)=z/5 and perpendicular to the plane x-y+z+2=0.

The line through of the plane passing through the lines (x-4)/(1)=(y-3)/(1)=(z-2)/(2) and (x-3)/(1)=(y-2)/(-4)=(z)/(5) is

The straight line (x+2)/(5) = (z-3)/( 1) , y=2 is

Find the equation of the plane containing the lines (x-5)/4=(y-7)/4=(z+3)/(-5)a n d(x-8)/7=(y-4)/1=(z-5)/3dot

The equation of the plane containing the line 2x-5y+z=3, x+y+4z=5 and parallel to the plane x+3y+6z=1 , is

The sine of the angle between the line (x-2)/(3) = (y-3)/(4) = (z-4)/(5) and the plane 2x-2y+z=5 is

If the straight lines (x-1)/(2)=(y+1)/(k)=(z)/(2) and (x+1)/(5)=(y+1)/(2)=(z)/(k) are coplanar, then the plane(s) containing these two lines is/are