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If the line x=alpha divides the area of ...

If the line `x=alpha` divides the area of region `R={(x,y) in R^(2): x^(3)leylex, 0le xle 1}` into two equal parts, then

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The correct Answer is:
2
`A={(x,y):0le ylex|x|+1 and -1lexle1}`
`A{(x,y): 0leylex^(2)+1 and 0lexle1}`
`uu{(x, y):0leyle-x^(2)+1-lexle0}`

Area `=int_(-1)^(0)(1-x^(2))dx+int_(0)^(1)(x^(2)+1)dx="2 sq. units"`
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