If the angular momentum of a planet of mass m, moving around the Sun in a circular orbit is L, about the center of the Sun, its areal velocity is :

Options

A. `L/(2m)`
B. `(4L)/m`
C. `L/M`
D. `(2L)/m`

Answer

A

Explanation

`dA=1/2 R^(2) d theta`
`(dA)/(dt)=1/2 R^(2)(d theta)/(dt)=(R^(2))/2 omega`
`L=mR^(2) omega`
`:.(dA)/(dt)=(R^(2))/2(L/(mR^(2)))=L/(2m)` i.e.