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A mixture of 2 moles of helium gas ( (at...

A mixture of 2 moles of helium gas (` (atomic mass)=4a.m.u` ) and 1 mole of argon gas ( `(atomic mass)=40a.m.u` ) is kept at 300K in a container. The ratio of the rms speeds `((v_(rms)(helium))/((v_(rms)(argon))` is

A

3.16

B

0.45

C

2.24

D

0.32

Text Solution

Verified by Experts

The correct Answer is:
A
`v_(rms) prop sqrt(T/m)`. For same temperature `v_(rms) prop 1/(sqrt(m))`
`implies(v_("rms")("helium"))/(v_(rms)("argon"))=sqrt((m("arg on"))/(m("helium")))=sqrt(40/4)=sqrt(10) ~~ 3.16`
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