Three blocks A, B and C are lying on a smooth horizontal surface, as shown in the figure. A and B have equal masses, m while C has mass M. Block A is given an inita speed v towards B due to which it collides with B perfectly inelastically. The combined mass collides with C, also perfectly inelastically `(5)/(6)th` of the initial kinetic energy is lost in whole process. What is balue of M/m?

Answer

4

Explanation

`P=` constant `=mv`
Loss is `KE=5/6` th of `KE_(i)`
`impliesKE_(f)=1/6` the of `KE_(i)implies(P^(2))/(2(M+2m))=1/6 (P^(2))/(2m)`
`impliesM+2m=6mimpliesM=4m`