For a uniformly charged ring of radius R, the electric field on its exis has the largest magnitude at a distance h from its centre. Then value of h is :

Answer

2

Explanation

`B=(mu_(0)IR^(2))/(2(R^(2)+h^(2))^(3//2))`
For B to be maximum `(dB)/(dh)=0impliesh=+-R/(sqrt(2))`