The highest value of the calculated spin-only magnetic moment (in BM) among all the transition metal complexes corresponds to x unpaired electrons in transition metal ion. The numerical value of x is _________.

Options

A. (1) 5
B. (2) 3
C. (3) 6
D. (4) 4

Explanation

To determine the highest value of the calculated spin-only magnetic moment (in Bohr magnetons, BM) among all transition metal complexes, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding the Formula**: The spin-only magnetic moment (μ) is calculated using the formula:
\[ \mu = \sqrt{n(n + 2)} \]
where \( n \) is the number of unpaired electrons.

2. **Identifying Maximum Unpaired Electrons**: In transition metals, the d-orbitals can accommodate a maximum of 10 electrons. However, when considering unpaired electrons, the maximum number of unpaired electrons in a d-subshell is 5. This occurs in a half-filled d-subshell configuration.

3. **Substituting Maximum Unpaired Electrons**: If we take \( n = 5 \) (the maximum number of unpaired electrons), we can substitute this into the formula:
\[ \mu = \sqrt{5(5 + 2)} = \sqrt{5 \times 7} = \sqrt{35} \]

4. **Calculating the Magnetic Moment**: Now, we compute \( \sqrt{35} \):
\[ \mu \approx 5.92 \, \text{BM} \]

5. **Conclusion**: Since the maximum number of unpaired electrons \( x \) that corresponds to this magnetic moment is 5, we conclude that:
\[ x = 5 \]

### Final Answer:
The numerical value of \( x \) is **5**.