Home
Class 12
CHEMISTRY
The amount of urea required to prepare 1...

The amount of urea required to prepare 1L of its 0.1 M aqueous solution is _______ g.

Text Solution

Verified by Experts

The correct Answer is:
6
Number of moles `=M xxV=(0.1)(1)=0.1` moles
`g_("urea") = 0.1xx60=6g`
Promotional Banner

Topper's Solved these Questions

  • JEE MAIN REVISION TEST-3 (2020)

    VMC MODULES ENGLISH|Exercise CHEMISTRY (SECTION 2)|5 Videos

  • JEE Main Revision Test-20 | JEE-2020

    VMC MODULES ENGLISH|Exercise CHEMISTRY|25 Videos

  • JEE Main Revision Test-6 | JEE-2020

    VMC MODULES ENGLISH|Exercise CHEMISTRY|25 Videos

Similar Questions

Explore conceptually related problems

The mass of NaCl required to prepare 0.1 m aqueous solution in 1kg water is

The amount of suga (C_(12)H_(22)O_(11)) required to prepare 2L of its 0.1 M aqueous solution is

The mass of NaCl required to prepare 0.4 m aqueous solution in 1kg water is

The mass of NaCl required to prepare 0.2 m aqueous solution in 1kg water is

The mass of NaCl required to prepare 0.3 m aqueous solution in 1kg water is

The mass of NaCl required to prepare 0.5 m aqueous solution in 1kg water is

The mass of NaCl required to prepare 0.6 m aqueous solution in 1kg water is

Mass of NaCl required to prepare 0.01 m aqueous solution in 1kg water is

The mass of NaCl required to prepare 0.03 m aqueous solution in 1kg water is

The mass of NaCl required to prepare 0.02 m aqueous solution in 1kg water is