Home
Class 12
MATHS
The tangent to the curve yt=xe^(x^2) pas...

The tangent to the curve `yt=xe^(x^2)` passing through the point (1,e) also passes through the point

A

(3, 6e)

B

`((5)/(3), 2e)`

C

`((4)/(3), 2e)`

D

(2, 3e)

Text Solution

Verified by Experts

The correct Answer is:
C

Tangent to the curve `y=xe^(x^(2))`
Point (1, e) lie on the curve
(Slope of tangent) `=(dy)/(dx)"|"_(1,e)=e^(x^(2))+xe^(x^(2)) xx 2x=e^(x^(2))(1+2x^(2))=e(1+2)=3e`
Equation of tangent
`(y-e)/(x-1)=3e`
`y=3xe-2e`
At `x=(4)/(3)`
`y=3xx(4)/(3)(e)-2e=2e`
We get `y=2e`
So this point `((4)/(3), 2e)` will lie on tangent
Promotional Banner

Topper's Solved these Questions

  • JEE MAIN REVISION TEST-3 (2020)

    VMC MODULES ENGLISH|Exercise MATHEMATICS (SECTION 2)|5 Videos
  • JEE Main Revision Test-20 | JEE-2020

    VMC MODULES ENGLISH|Exercise MATHEMATICS|25 Videos
  • JEE Main Revision Test-6 | JEE-2020

    VMC MODULES ENGLISH|Exercise MATHEMATICS|25 Videos

Similar Questions

Explore conceptually related problems

The tangent to the curve y=xe^(x^2) passing through the point (1,e) also passes through the point

The tangent to the curve y=x^2-5x+5. parallel to the line 2y=4x+1, also passes through the point :

Plot the points (3,\ 5)a n d\ (-1,\ 3) on a graph paper and verify that the straight line passing through these points also passes through the point (1,\ 4)dot

Given the curves y=f(x) passing through the point (0,1) and y=int_(-oo)^(x) f(t) passing through the point (0,(1)/(2)) The tangents drawn to both the curves at the points with equal abscissae intersect on the x-axis. Then the curve y=f(x), is

The circle passing through the point (-1,0) and touching the y-axis at (0,2) also passes through the point:

For the curve y=4x^3-2x^5, find all the points at which the tangent passes through the origin.

Curves y=f(x) passing through the point (0,1) and y=int_-oo^x f(t) dt passing through the point (0,1/n) are such that the tangents drawn to them at the point with equal abscissae intersect on x-axis. Answer the question:The equation of curve y=f(x)

Curves y=f(x) passing through the point (0,1) and y=int_-oo^x f(t) dt passing through the point (0,1/n) are such that the tangents drawn to them at the point with equal abscissae intersect on x axis. find Curve y=f(x)

Curves y=f(x) passing through the point (0,1) and y=int_-oo^x f(t) dt passing through the point (0,1/n) are such that the tangents drawn to them at the point with equal abscissae intersect on x axis

For the curve y=4x^3-2x^5, find all the points at which the tangents pass through the origin.