The co-ordination number of Th in `[Th (C_(2) O _(4))_(4) ]^(2-) is : (C_(2) O _(4) ^(2-)=` Oxalato)

Options

A. a. 10
B. b. 8
C. c. 6
D. d. 4

Explanation

To determine the coordination number of Thorium (Th) in the complex \([Th(C_2O_4)_4]^{2-}\), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Central Metal Atom**:
The central metal atom in the complex is Thorium (Th).

2. **Identify the Ligand**:
The ligand present in the complex is oxalate, represented as \(C_2O_4^{2-}\).

3. **Determine the Denticity of the Ligand**:
The oxalate ligand \(C_2O_4^{2-}\) is a bidentate ligand. This means that each oxalate ion can form two coordinate bonds with the central metal atom.

4. **Count the Number of Ligands**:
In the given complex, there are 4 oxalate ligands attached to the Thorium atom.

5. **Calculate the Total Coordination Number**:
Since each oxalate ligand forms 2 bonds, and there are 4 such ligands, the total number of bonds formed (which gives us the coordination number) is calculated as follows:
\[ \text{Coordination Number} = \text{Number of Ligands} \times \text{Bonds per Ligand} = 4 \times 2 = 8 \]

6. **Conclusion**:
Therefore, the coordination number of Thorium in the complex \([Th(C_2O_4)_4]^{2-}\) is 8.

### Final Answer:
The coordination number of Th in \([Th(C_2O_4)_4]^{2-}\) is **8**.

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