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An ideal gas is enclosed in a cylinder a...

An ideal gas is enclosed in a cylinder at pressure of 2atm and temperature, 300K. The mean time between two successive collisions is `6xx10^(-8)` s. If the pressure is doubled and temperature is increased to 500K, the mean time between two successive collisions will be close to:

A

`4 xx 10^(-8) s`

B

`3 xx 10^(-6) s`

C

`2 xx 10^(-7) s`

D

`0.5 xx 10^(-8) s`

Text Solution

Verified by Experts

The correct Answer is:
A
Time between successive collision = `t prop (sqrt(T))/(P)`
So, `6 xx 10^(-8) prop (sqrt(300))/(2)` and `t_(2) prop (sqrt(500))/(4)`
Solving , `t = sqrt(15) xx 10^(-8) ~~ 4 xx 10^(-8) sec`
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