In the given circuit diagram, the currents, `I_1=-0.3A,I_4=0.8A` and `I_5=0.4A`, are flowing as shown. The currents `I_2,I_3` and `I_6` respectively, are :

Options

A. `-0.4 A, 0.4 A, 1.1 A`
B. `0.4 A, 1.1 A , 0.4 A`
C. `1.1 A, -0.4A, 0.4 A`
D. `1.1 A, 0.4 A, 0.4 A`

Answer

D

Explanation

`I_(1) = -0.3 A, I_(4) = 0.8 A, I_(5) = 0.4 A`
`I_(6) + I_(3) = I_(2) + I_(1)`
`I_(6) + I_(3) = I_(2) - 0.3 A` …(i)
`I_(5) + I_(3) = I_(4)` …(ii)
`0.4 + I_(3) = 0.8, I_(3) = 0.4`
`I_(2) + I_(1) = I_(4)` ….(iii)
`I_(2) - 0.3 = 0.8`
`I_(2) = 1.1 A, I_(5) = I_(6) = 0.4 A`