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The de-Broglie wavelength of an electron...

The de-Broglie wavelength of an electron in 4th orbit is (where, r=radius of 1st orbit)

A

`1.50`

B

`0.75`

C

`1.0`

D

`0.40`

Text Solution

Verified by Experts

The correct Answer is:
B
`2pi r = n lambda`
`2pi xx a_(0) (n^(2))/(z) = n xx 1.5 pi a_(0)`
`2pi xx (n)/(z) = 1.5 pi`
`(n)/(z) = (1.5)/(2) = 0.75`
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