The volume strength of g1 M `H_(2)O_(2)` is : (Molar mass of `H_(2)O_(2) = 34 g mol^(-1)`)

Explanation

To find the volume strength of 1 M \( H_2O_2 \), we will follow these steps:

### Step 1: Understand the concept of volume strength
Volume strength is defined as the volume of oxygen gas (in liters) that is liberated when one volume of hydrogen peroxide decomposes completely.

### Step 2: Write the balanced equation for the decomposition of \( H_2O_2 \)
The balanced equation for the decomposition of hydrogen peroxide is:
\[ 2 H_2O_2 \rightarrow 2 H_2O + O_2 \]

### Step 3: Determine the moles of \( H_2O_2 \) and the corresponding moles of \( O_2 \)
From the balanced equation, we see that 2 moles of \( H_2O_2 \) produce 1 mole of \( O_2 \). Therefore, 1 mole of \( H_2O_2 \) will produce:
\[ \frac{1}{2} \text{ moles of } O_2 \]

### Step 4: Calculate the volume of \( O_2 \) produced at STP
At standard temperature and pressure (STP), 1 mole of any gas occupies 22.4 liters. Thus, the volume of \( O_2 \) produced from 1 mole of \( H_2O_2 \) is:
\[ \text{Volume of } O_2 = \frac{1}{2} \times 22.4 \text{ L} = 11.2 \text{ L} \]

### Step 5: Calculate the volume strength
Since the volume strength is defined as the volume of oxygen produced from 1 liter of \( H_2O_2 \), and we have calculated that 1 mole of \( H_2O_2 \) (which is 1 L of 1 M solution) produces 11.2 L of \( O_2 \), the volume strength of 1 M \( H_2O_2 \) is:
\[ \text{Volume strength} = 11.2 \]

### Final Answer:
The volume strength of 1 M \( H_2O_2 \) is **11.2**.

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