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There are m men and two women participat...

There are m men and two women participating in a chess tournament. Each participant plays two games with every other participant. If the number of games played by the men between themselves exceeds the number of games played between the men and the women by 84, then teh value of m is

A

12

B

9

C

7

D

11

Text Solution

Verified by Experts

The correct Answer is:
A

For each of the m men game played will be (m-1), so total game between 2 mens will be (m)(m-1) also for each women game played with men will be 2m, so total matches will be 2.2m. Acc to question.
(m)(m-1) = 2.2m + 84
`m^(2) - m = 4m + 84`
`m^(2) - 12m + 7m - 84 = 0`
`(m+7)(m-12) = 0`
`m = -7 xx m = 12`
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