0.27 g of a long chain fatty acid was dissolved in ` 100 cm^ 3 ` of hexane. 10 mL of this solution was added dropwise to the surface of water in a round watch glass. Hexane evaporates and a monolayer is formed. The distance from edge to centre of the watch glass is 10 cm. The height of the monolayer is ` 10 ^( -x ) ` m. what is numerical value of `x ` ? [Density of fatty acid ` = 0.9 g cm ^ ( -3) , pi = 3 ` ]

Explanation

To solve the problem step-by-step, we will follow the given information and apply the relevant formulas.

### Step 1: Calculate the mass of fatty acid in 10 mL of solution
Given that 0.27 g of fatty acid is dissolved in 100 mL of hexane, we can find the mass of fatty acid in 10 mL of the solution.

\[ \text{Mass in 10 mL} = \frac{0.27 \, \text{g}}{100 \, \text{mL}} \times 10 \, \text{mL} = 0.027 \, \text{g} \]
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