Let y=y(x) be the solution of the differential equation,
`(x^(2)+1)^(2)dy/dx+2x(x^(2)+1)y=1` such that y(0) =0. If
`sqrta y(1)=pi/32`,then tha value of 'a' is

Explanation

To solve the given differential equation and find the value of 'a', we will follow these steps:

### Step 1: Rewrite the Differential Equation
The given differential equation is:
\[ (x^2 + 1)^2 \frac{dy}{dx} + 2x(x^2 + 1)y = 1 \]
We can rewrite it by dividing through by \((x^2 + 1)^2\):
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