The efficiency of a heat engine is `1//6`Its efficiency double when the temperature of sink decrease by `62^(@)C` its efficiency doubles.Then,What is the temperature of source?

Options

A. `99^(@)C
B. `37^(@)C,
C. `62^(@)C
D. `124^(@)C,

Answer

B

Explanation

`1/6=1-(T_(2))/(T_(1))implies(T_(2))/(T_(1))=5/6`…….1
`=1/3=1-((T_(2)-62))/(T_(1))implies((T_(2)-62)/(T_(1)))=2/3`…….2
From 1 and 2
`1/6=62/(T_(1))impliesT_(1)=372k` or `99^(@)C`
`T_(2)=5/6xx372=5xx62=310K` or `37^(@)C`