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Consider an electron in a hydrogen atom,...

Consider an electron in a hydrogen atom, revolving in its second excited state (having radius `4.65 Å`). The de-Broglie wavelength of this electron is :

A

`12.9Å`

B

`6.6Å`

C

`9.7Å`

D

`3.5Å`

Text Solution

Verified by Experts

The correct Answer is:
C
`mVr=(3h)/(rpi)(n=3)`
`mV=(3h)/(2pixxr)=(3h)/(2.pir)`
`lamda=h/(mV)=(2.h pi r)/(3.h)=(2 pi r)/3=2/3xx4.65Å=9.7Å`
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