A solution is prepared by dissolving 0.6 g of urea (molar mass `=60 g"mol"^(-1)`) and 1.8 g of glucose (molar mass `=180g"mol"^(-1)`) in 100 mL of water at `27^(@)C`. The osmotic pressure of the solution is:
`(R=0.08206L "atm"K^(-1)"mol"^(-1))`

Options

A. 1.64 atm
B. 4.92 atm
C. 8.2 atm
D. 2.46 atm

Answer

B

Explanation

`pi=pi_(1)+pi_(2)`
`pi_(1)=` osmotic pressure of urea solution.
`pi_(2)=` osmotic pressure of glucose solution.
`pi_(1)=C_(1)RT=pi_(2)=C_(2)RT`
`C_(1)=(0.6//60)/0.1=0.1M`
`C_(2)=(1.8//180)/0.1=0.1M`
`pi=pi_(1)+pi_(2)=0.1RT+0.1RT`
`pi=2(0.1RT)=0.2xx24.6=4.92atm`.