Benzene diazonium chloride on reaction with aniline in the presence of dilute hydrochloric acid gives :

Options

A.
B.
C.
D.

Explanation

To solve the problem of what benzene diazonium chloride reacts with aniline in the presence of dilute hydrochloric acid to produce, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
- Benzene diazonium chloride (C6H5N2Cl) consists of a benzene ring with a diazonium group (-N2^+) and a chloride ion (Cl^-).
- Aniline (C6H5NH2) is a benzene ring with an amino group (-NH2).

2. **Understand the Reaction Conditions**:
- The reaction occurs in the presence of dilute hydrochloric acid (HCl). This environment is conducive for electrophilic substitution reactions.

3. **Recognize the Type of Reaction**:
- This reaction is a coupling reaction, where the diazonium compound acts as an electrophile and reacts with the nucleophilic aniline.

4. **Determine the Electrophilic Behavior**:
- The diazonium ion (C6H5N2^+) is a good electrophile due to the positive charge on the nitrogen atom. It will seek to react with the nucleophilic amino group of aniline.

5. **Predict the Product**:
- The reaction will occur at the para position of the aniline due to steric hindrance and resonance stabilization. The product formed will be para-amino diazo benzene.

6. **Write the Structure of the Product**:
- The final product can be represented as C6H4(NH2)(N2) (where the diazo group is at the para position relative to the amino group). This compound is known as para-amino diazo benzene, which is a yellow dye.

7. **Conclusion**:
- The product of the reaction between benzene diazonium chloride and aniline in the presence of dilute hydrochloric acid is para-amino diazo benzene.

### Final Answer:
The product formed is para-amino diazo benzene (option C).

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