Home
Class 12
CHEMISTRY
25 g of an unknown hydrocarbon contains ...

25 g of an unknown hydrocarbon contains 24 g of carbon. 25 g of this hydrocarbon on burning produces x gm of `H_(2)O`. The numerical value of x is_____.

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will follow these calculations: ### Step 1: Determine the mass of hydrogen in the hydrocarbon Given that the total mass of the hydrocarbon is 25 g and it contains 24 g of carbon, we can find the mass of hydrogen in the hydrocarbon. \[ \text{Mass of Hydrogen} = \text{Total mass of hydrocarbon} - \text{Mass of Carbon} = 25 \, \text{g} - 24 \, \text{g} = 1 \, \text{g} \] ### Step 2: Write the general formula for the combustion of a hydrocarbon The general formula for the combustion of a hydrocarbon (CxHy) can be written as: \[ \text{CxHy} + O_2 \rightarrow CO_2 + H_2O \] ### Step 3: Determine the moles of carbon and hydrogen - The molar mass of carbon (C) is 12 g/mol. - The molar mass of hydrogen (H) is 1 g/mol. Calculating the moles of carbon: \[ \text{Moles of Carbon} = \frac{\text{Mass of Carbon}}{\text{Molar Mass of Carbon}} = \frac{24 \, \text{g}}{12 \, \text{g/mol}} = 2 \, \text{mol} \] Calculating the moles of hydrogen: \[ \text{Moles of Hydrogen} = \frac{\text{Mass of Hydrogen}}{\text{Molar Mass of Hydrogen}} = \frac{1 \, \text{g}}{1 \, \text{g/mol}} = 1 \, \text{mol} \] ### Step 4: Determine the moles of water produced From the combustion reaction, we know that: - 1 mole of C produces 1 mole of CO2. - 2 moles of H produces 1 mole of H2O. Thus, for 2 moles of carbon, we will produce 2 moles of CO2 and for 1 mole of hydrogen, we will produce: \[ \text{Moles of H2O} = \frac{\text{Moles of H}}{2} = \frac{1 \, \text{mol}}{2} = 0.5 \, \text{mol} \] ### Step 5: Calculate the mass of water produced The molar mass of water (H2O) is: \[ \text{Molar Mass of H2O} = 2 \times 1 + 16 = 18 \, \text{g/mol} \] Now, we can calculate the mass of water produced: \[ \text{Mass of H2O} = \text{Moles of H2O} \times \text{Molar Mass of H2O} = 0.5 \, \text{mol} \times 18 \, \text{g/mol} = 9 \, \text{g} \] ### Final Answer The numerical value of \( x \) (the mass of water produced) is: \[ \boxed{9} \, \text{g} \]

To solve the problem step by step, we will follow these calculations: ### Step 1: Determine the mass of hydrogen in the hydrocarbon Given that the total mass of the hydrocarbon is 25 g and it contains 24 g of carbon, we can find the mass of hydrogen in the hydrocarbon. \[ \text{Mass of Hydrogen} = \text{Total mass of hydrocarbon} - \text{Mass of Carbon} = 25 \, \text{g} - 24 \, \text{g} = 1 \, \text{g} \] ...
Promotional Banner

Topper's Solved these Questions

  • QUIZ

    VMC MODULES ENGLISH|Exercise CHEMISTRY|30 Videos
  • REVISION TEST-2 JEE

    VMC MODULES ENGLISH|Exercise CHEMISTRY|25 Videos

Similar Questions

Explore conceptually related problems

25 g of an unknown hydrocarbon upon burning produces 88 g of CO_2 and 9 g of H_2O . This unknown hydrocarbon contains

10 ml of gaseous hydrocarbon on combution gives 20ml of CO_(2) and 30ml of H_(2)O(g) . The hydrocarbon is :-

A gaseous hydrocarbon gives upon combustion, 0.72 g of water and 3.08 g of CO_(2) . The empirical formula of the hydrocarbon is

3g of a hydrocarbons on combusion in excess of oxygen produces 8.8g of CO_(2) and 5.4g of H_(2)O . The data illustrates the law of:

A hydrocarbon (containing only carbon, hydrogen) on complete combustion gave 4.4 gm CO_(2) and 1.8 gm H_(2)O . What is it's empirical formula

A definite amount of gaseous hydrocarbon having ("carbon atoms less than" 5) was burnt with sufficient amount of O_(2) . The volume of all reactants was 600mL . After the explosion the volume of the product [CO_(2)(g) and H_(2)O (g)] was found to be 700 mL under the similar conditions. The molecular formula of the compound is ?

4.4 gms of a hydrocarbon on complete combustion produced 13.2 gms of CO_(2) and 7.2 gms of H_(2)O . What is the hydrocarbon?

6g of a hydrocarbon on combustion in excess of oxygen produces 17.6g of CO_(2) and 10.8g of H_(2)O . The data illustrates the law of :

10mL of gaseous hydrocarbon on combustion gives 40ml of CO_(2)(g) and 50mL of H_(2)O (vapour) The hydrocarbon is .

12.8 gm of an organic compound containing C, H and O and undergoes combustion to produce 25.56 gm CO_(2) and 10.46 gm of H_(2)O . What is the empirical formula of compound.

VMC MODULES ENGLISH-REVISION TEST-15 JEE - 2020-CHEMISTRY
  1. The compound used in the treatment of lead poisoning is :

    Text Solution

    |

  2. Among the following, the INCORRECT statement about colloids is :

    Text Solution

    |

  3. Assertion: Vinyl halides do not undergo substitution reaction. Reaso...

    Text Solution

    |

  4. In the following skew conformatioin of ethane, H'-C-C-H'' dihedral a...

    Text Solution

    |

  5. C-C bond length is maximum in

    Text Solution

    |

  6. A solution is prepared by dissolving 0.6 g of urea (molar mass =60 g"m...

    Text Solution

    |

  7. Heating of 2-chloro-1-phenylbutane with EtOK/EtOH gives X as the major...

    Text Solution

    |

  8. In comparison to B, Be has

    Text Solution

    |

  9. The decreasing order of electrical conductivity of the following aqueo...

    Text Solution

    |

  10. Benzene diazonium chloride on reaction with aniline in the presence of...

    Text Solution

    |

  11. Which one of the following is likely to give a precipitate with AgNO(3...

    Text Solution

    |

  12. The correct statement is :

    Text Solution

    |

  13. The temporary hardness of a water sample is due to compound X. Boiling...

    Text Solution

    |

  14. The INCORRECT statement is :

    Text Solution

    |

  15. Which of the given statements is INCORRECT about glycogen ?

    Text Solution

    |

  16. The molar solubility of Cd(OH)(2) is 1.84xx10^(-5)M in water. The expe...

    Text Solution

    |

  17. NO(2) required for a reaction is produced by the decomposition of N(2)...

    Text Solution

    |

  18. 25 g of an unknown hydrocarbon contains 24 g of carbon. 25 g of this h...

    Text Solution

    |

  19. The coordination numbers of Co in [Co(Cl)(en)(2)]Cl is. (en=ethane-1...

    Text Solution

    |

  20. The ratio of number of atoms present in a simple cubic, body centered ...

    Text Solution

    |