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The ratio of number of atoms present in ...

The ratio of number of atoms present in a simple cubic, body centered cubic and face centered cubic structure are x: y : z. The numerical value of sum of x, y and z is _______ .

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To solve the problem, we need to determine the effective number of atoms present in three types of crystal structures: simple cubic (SC), body-centered cubic (BCC), and face-centered cubic (FCC). We will denote the effective number of atoms in these structures as x, y, and z respectively. ### Step 1: Determine the effective number of atoms in Simple Cubic (SC) In a simple cubic structure, atoms are located only at the corners of the cube. There are 8 corners in a cube, and each corner atom is shared by 8 adjacent unit cells. - Effective number of atoms in SC: \[ \text{Effective atoms} = \frac{1}{8} \times 8 = 1 \] Thus, we have \( x = 1 \). ### Step 2: Determine the effective number of atoms in Body-Centered Cubic (BCC) In a body-centered cubic structure, there are atoms at each corner of the cube and one additional atom in the center of the cube. - Effective number of atoms in BCC: \[ \text{Effective atoms} = \left(\frac{1}{8} \times 8\right) + 1 = 1 + 1 = 2 \] Thus, we have \( y = 2 \). ### Step 3: Determine the effective number of atoms in Face-Centered Cubic (FCC) In a face-centered cubic structure, atoms are located at each corner and at the center of each face. Each corner atom is shared among 8 unit cells, and each face atom is shared between 2 unit cells. - Effective number of atoms in FCC: \[ \text{Effective atoms} = \left(\frac{1}{8} \times 8\right) + \left(\frac{1}{2} \times 6\right) = 1 + 3 = 4 \] Thus, we have \( z = 4 \). ### Step 4: Write the ratio of the number of atoms Now we have: - \( x = 1 \) (for SC) - \( y = 2 \) (for BCC) - \( z = 4 \) (for FCC) The ratio of the number of atoms is: \[ x : y : z = 1 : 2 : 4 \] ### Step 5: Calculate the sum of x, y, and z Now, we can find the sum: \[ x + y + z = 1 + 2 + 4 = 7 \] ### Final Answer The numerical value of the sum of \( x, y, \) and \( z \) is **7**. ---

To solve the problem, we need to determine the effective number of atoms present in three types of crystal structures: simple cubic (SC), body-centered cubic (BCC), and face-centered cubic (FCC). We will denote the effective number of atoms in these structures as x, y, and z respectively. ### Step 1: Determine the effective number of atoms in Simple Cubic (SC) In a simple cubic structure, atoms are located only at the corners of the cube. There are 8 corners in a cube, and each corner atom is shared by 8 adjacent unit cells. - Effective number of atoms in SC: \[ \text{Effective atoms} = \frac{1}{8} \times 8 = 1 ...
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