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A process has Delta H = 8 K J mol^(-1) ...

A process has `Delta H = 8 K J mol^(-1) " and " Delta S = 80JK^(-1) mol^(-1)` The temperature at which the process will be in equilibrium is ____________ K.

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To find the temperature at which the process will be in equilibrium, we can use the relationship between Gibbs free energy (ΔG), enthalpy (ΔH), and entropy (ΔS). The equation is: \[ \Delta G = \Delta H - T \Delta S \] At equilibrium, ΔG = 0. Therefore, we can rewrite the equation as: ...
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VMC MODULES ENGLISH-JEE MAIN REVISION TEST - 19-CHEMISTRY
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