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A motor cyclist moving with a velosity o...

A motor cyclist moving with a velosity of `72 km h^(-1)` on a flat road takes a turn on the road at a point where the radius of curvature of the road is 20km. The acceleration due to gravity is `10 ms^(-2)`. IN order to avoid skidding , he must not bend with respesct to the vertical plane by an angle greater then

A

`theta=tan^(-1) 6`

B

`theta=tan^(-1)2`

C

`theta=tan^(-1)(25.92)`

D

`theta=tan^(-1)4`

Text Solution

Verified by Experts

The correct Answer is:
B
`mg L/2 "sin" theta = (mv^2)/R L/2 "cos" theta`
`tan theta=v^2/(gR)`
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VMC MODULES ENGLISH-JEE Main Revision Test-20 | JEE-2020 -PHYSICS
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