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A solution has 1:4 mole ratio of pentane...

A solution has `1:4` mole ratio of pentane to hexane . The vapour pressure of pure hydrocarbons at `20^@C`are `440` mm Hg for pentane and `120`mm Hg for hexane .The mole fraction of pentane in the vapour phase is

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The correct Answer is:
D
`P=440xx1/5+120xx4/5`=184 mm Hg
`(X_"pentane")_"vapour phase" = (440xx1/5)/184` = 0.478 mm Hg.=0.48 mm Hg
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