If the continued product of three numbers in GP is 216 and the sum of their products in pairs is 156, then find the sum of three numbers.

Answer

B

Explanation

Let numbers are `a/r`, a, ar
Then `a/r xx a xx ar =216 rArr a=6`
And sum of products in pair =156
`rArr a/rxxa+axxar+arxxa/r=156 rArr 3r^2-10r+3=0 rArr r=1/3` or 3
So required numbers are 18,6,2 or 2, 6 ,18
Hence, the sum of numbers is 26.